2x+4x=3+3x^2

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Solution for 2x+4x=3+3x^2 equation: 



2x+4x=3+3x^2

We move all terms to the left:

2x+4x-(3+3x^2)=0

We add all the numbers together, and all the variables

-(3+3x^2)+6x=0

We get rid of parentheses

-3x^2+6x-3=0

a = -3; b = 6; c = -3;
Δ = b2-4ac
Δ = 62-4·(-3)·(-3)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{-6}=1$

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